NERD ANALAYSIS TIME!
The turrets depicted appear to be Dual Heavy Beam Lasers, which have a 17m long main axis.
An offhand comparison suggests to me that the 'solar panels' could not be (generously) more than 10m long and 30m wide, for a total area of 300m2 on each panel, across 8 panels = 2400m2, or around 25833 square feet.
This website suggests that solar panels, on average, produce 8-10 watts per s.f.; going generous, our square footage will provide around 258 kW of energy. Now let's be generous again, and say that through NANITES! the sisters have managed to make solar panels 300% more efficient, giving a total yield of 775 kW.
According to this research, a large modern hospital (900 beds, 1600 occupants/hr) will require on average around 2.4 mW of electricity; this includes food preparation, staff areas, and building AC as well as medical equipment. Considering that the Nestor is a battleship, it will also have major electrical loads such as artificial gravity, air and water recycling, and large-scale internal supply cold storage.
tl;dr - even being incredibly generous with power production and assuming all other shipboard systems are going to be put into cold shutdown, those solar panels aren't going to produce nearly enough energy to power medical bays of any significant size.
[/massive nerdiness]
ohgod why do I do these things
Additional nerd analysis.
Your solar energy calculator likely assumes commercially available solar panels available from some where like
Home Depot. These are marketed as producing 390-Watts. They have an area of ~1.625 m2. This gives them ~240 W/m2.
The
solar constant at 1 AU from a G2V class star (ie the Sun) is ~1362 W/m2. With the atmosphere and using the Standard Testing Conditionswe will assume 1000 W/m2.
This tells us that the Home Depot panel, ignoring atmospheric absorption, has an efficiency of 17.6%-24%.
So, the 300% increase gets us to ~53-72% efficiency. The lower bound is very near the
current state of the art cell efficiency - 44.4%.
Accepting your 2400 m2 approximation of the solar panel area and assuming a single layer of cells*, 80% solar cell efficiency (less than 2x the current SOA), at 1 AU from a G2V class star (~1362 W/m2), incidence angle is 0 (as in straight on and optimal), we get...
2,615,040 W or 2.6 MW*This assumption is crucial as there is currently
research ongoing utilizing layered solar cells with will absorb more light at a wider spectrum.
There are however important assumptions I made, like the distance from the star, the type of star, and the panel incidence angle to the star light. Solar power suffers from the
inverse-square law, which means even in the Sol system it is useful out to Mars and the inner Main Asteroid Belt. A
red dwarf for example has at the top end only 10% the luminosity of Sol and therefore Solar power is effectively
useless. Lastly
incidence angle changes how much solar energy is collected, this however could potentially be
resolved with nanites.
Thus outside of specific star systems and ranges, there may simply not be enough solar flux (W/m2 of light) to provide the power.
My education & job revolves around spacecraft engineering.